Formula_22976

\[\begin{gathered}A_{\Lambda}=\left\{a_{i j}^{(\Lambda)}\right\}=\left(B_{\Lambda}\right)^{-1}, \\B_{\Lambda}=\left\{b_{i j}\right\}, i, j=1, \ldots, n, \\b_{i j}=b_{t_{i} t_{j}}, a_{i}=a_{t_{j}}\end{gathered}\]